In one hour, a man rows his canoe against the stream at 11 km/h and along the stream at 23 km/h. What is the speed (in km/h) of the stream?
Let's assume the speed of the canoe in still water is 'B'.
The speed of the stream is 'C'.
A man rows his canoe against the stream at 11 km/h and along the stream at 23 km/h.
B-C = 11Â Â Eq.(i)
B+C = 23Â Â Â Eq.(ii)
2B = 11+23 = 34
B = 17
Put the value of 'B' in Eq.(i).
17-C = 11
C = 17-11
Speed of the stream =Â C = 6 km/h
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