A man can finish a piece of work in 15 days. A woman can complete the same work in 10 days. Both work together for 5 days, then the man leaves. How many days will be taken by the woman tofinish the remaining work?

The man's 1 day's work = $$ \frac {1} {15}

The woman's 1 day's work = $$ \frac {1} {10}

1 day's work done by both man and woman together =  $$ \frac {1} {15} + $$ \frac {1} {10}

= $$\frac {(2+3)}{30}$$

= $$ \frac {5}{30}$$

= $$ \frac {1}{6}$$

They work together for 5 days. Hence the work done by both man and woman together = 5 $$ \times \frac {1}{6} $$ = $$ \frac {5}{6}$$

So, this work will be completed by the woman as men left after working for 5 days.

Hence 10 women will take to complete = 10 x $$ \frac {1}{6}$$ = $$ \frac {10}{6}$$ = $$ \frac {5}{3}$$ = 1 $$ \frac {2}{3}$$