A is twice as good as B and together they finish a piece of work in 16 days. The number of days taken by A alone to finish the work is
Let A's efficiency = $$2x$$ units/day
=> B's efficiency = $$x$$ units/day
=> (A+B)'s 1 day's work = $$(2x+x)=3x$$ units/day
$$\because$$ Together they complete work in 16 days
=> Total work to be done = $$16 \times 3x=48x$$ units
$$\therefore$$ Time taken by A alone to finish the work = $$\frac{48x}{2x}=24$$ days
=> Ans - (D)
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