Question 51

A is twice as good as B and together they finish a piece of work in 16 days. The number of days taken by A alone to finish the work is

Solution

Let A's efficiency = $$2x$$ units/day

=> B's efficiency = $$x$$ units/day

=> (A+B)'s 1 day's work = $$(2x+x)=3x$$ units/day

$$\because$$ Together they complete work in 16 days

=> Total work to be done = $$16 \times 3x=48x$$ units

$$\therefore$$ Time taken by A alone to finish the work = $$\frac{48x}{2x}=24$$ days

=> Ans - (D)

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