The maximum speed of a boat in still water is 27 km/h. Now this boat is moving downstream in a river flowing at 9 km/h. A man in the boat throws a ball vertically upwards with speed of 10 m/s. Range of the ball as observed by an observer at rest on the river bank, is _______ cm. (Take g = $$10 m/s^{2}$$)

Correct Answer: 2000

Boat speed downstream = 27+9 = 36 km/h = 10 m/s. Ball thrown at 10 m/s upward.

Time of flight = 2u/g = 2×10/10 = 2s. Range = horizontal speed × time = 10×2 = 20m = 2000 cm.

The answer is 2000.

Create a FREE account and get:

Predict your JEE Main percentile, rank & performance in seconds

Check Your Score Now

Ask our AI anything

AI can make mistakes. Please verify important information.

Download resources