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The freezing point (in $$^\circ C$$) of a solution containing 0.1 g of $$K_3[Fe(CN)_6](Mol. Wt. 329)$$ in 100 g of water $$(K_f = 1.86 K kg mol^{-1})$$ is
$$-2.3 \times 10^{-2}$$
$$-5.7 \times 10^{-2}$$
$$-5.7 \times 10^{-3}$$
$$-1.2 \times 10^{-2}$$
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