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Question 49
A person covers 40% of the distance from A to B at 8 km/h, 40% of the remaining distance at 9 km/h and the rest at 12 km/h. His average speed (in km/h) for the journey is:
Solution
Let the distance be 100 km.
40% of the distance = 40 kmÂ
Remaining distance = 100 - 40 = 60 km
40% of the remaining distance = 60 $$\times \frac{40}{100}$$ = 24 km
Remaining distance =Â 100 - 40 - 24 = 36 kmÂ
Average speed = total distance/total time = $$\frac{100}{\frac{40}{8} +Â \frac{24}{9} +Â \frac{36}{12}} = \frac{300}{32} = 9 \frac{3}{8}$$
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