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L.C.M. of (3,5,6,9) = 90
Now, the numbers of the form $$90k$$ will be divisible by 3,5,6,9, where $$k$$ is a natural number
Prime Factorization of 90 = $$3^2\times2\times5$$
Thus, in order to have both even powers, we need to multiply it by 10 = 900
=> Ans - (A)
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