Match List-I with List-II.
1-Bromopropane is reacted with reagents in List-I to give product in List-II

	List-I Reagent		List-II Product
A	KOH (alc)	I	Nitrile
B	KCN (alc)	II	Ester
C	AgNO$$_2$$	III	Alkene
D	H$$_3$$CCOOAg	IV	Nitroalkane

Choose the correct answer from the options given below

1-Bromopropane (CH₃CH₂CH₂Br) reacts with different reagents:

A. KOH (alc): Alcoholic KOH causes elimination (dehydrohalogenation) → produces alkene (propene) → Matches III

B. KCN (alc): CN⁻ from KCN acts as a nucleophile attacking through carbon → produces nitrile (butanenitrile) → Matches I

C. AgNO₂: Silver nitrite reacts with alkyl halides through nitrogen (Ag favors O-attack but with alkyl halides, AgNO₂ gives nitroalkane via N) → Actually, AgNO₂ gives nitroalkane (R-NO₂) because Ag⁺ being a soft acid favors the N-bound product → Matches IV (Nitroalkane)

D. CH₃COOAg: Silver acetate reacts with alkyl halide → produces ester (propyl acetate) → Matches II

The matching is: A-III, B-I, C-IV, D-II

This matches option 1.