CAT WhatsApp Group
Sign in
Please select an account to continue using cracku.in
↓ →
CAT WhatsApp Group
Expression : $$(\frac{1}{secA+tanA})^2$$
= $$(\frac{}{\frac{1}{cosA}+\frac{sinA}{cosA}})^2$$
= $$(\frac{cosA}{1+sinA})^2=\frac{cos^2A}{(1+sinA)^2}$$
= $$\frac{1-sin^2A}{(1+sinA)^2}=\frac{(1-sinA)(1+sinA)}{(1+sinA)^2}$$
= $$\frac{1-sinA}{1+sinA}$$
=> Ans - (C)
Create a FREE account and get:
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
