If 4x + 3y = 11 and 3x + 2y = 8, then (x,y) is

Equation 1 : $$(4x + 3y = 11)$$   $$\times$$ $$2$$

Equation 2 : $$(3x+2y=8)$$     $$\times$$ $$3$$

Multiplying equation (i) by 2 and equation (ii) by 3, we get :

=> $$8x+6y=22$$ -------------(iii)

and $$9x+6y=24$$ -----------(iv)

Subtracting equation (iii) from (iv), => $$(9x-8x)=(24-22)$$

=> $$x=2$$

Substituting it in equation (i), => $$3y=11-4(2)$$

=> $$3y=11-8=3$$

=> $$y=\frac{3}{3}=1$$

$$\therefore$$ $$(x,y)=(2,1)$$

=> Ans - (C)