Given below are two statements:
Statement (I) : In the Lanthanoids, the formation of $$Ce^{+4}$$ is favoured by its noble gas configuration.
Statement (II) : $$Ce^{+4}$$ is a strong oxidant reverting to the common +3 state.
In the light of the above statements, choose the most appropriate answer from the options given below:

Statement I: Formation of $$Ce^{4+}$$ is favoured by its noble gas configuration. $$Ce$$ has atomic number 58: $$[Xe]4f^15d^16s^2$$. Losing 4 electrons gives $$Ce^{4+}$$: $$[Xe]$$ — noble gas configuration. True.

Statement II: $$Ce^{4+}$$ is a strong oxidant reverting to the common +3 state. True — the +3 state is more stable for lanthanides, so $$Ce^{4+}$$ readily accepts an electron to become $$Ce^{3+}$$.

Both statements are true. The answer corresponds to Option (2).