The sum of the parallel sides of a trapezium is 12.4 cm. If the distance between the parallel sides is 3.5 cm, what is the area of this trapezium?
Sum of parallel sides of trapezium = 12.4 cm
Height of trapezium = 3.5 cm
Area of trapezium = $$\frac{1}{2} \times$$ (sum of parallel sides) $$\times$$ height
= $$\frac{1}{2} \times 12.4 \times 3.5$$
= $$6.2 \times 3.5 = 21.7$$ $$cm^2$$
=> Ans - (D)
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