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Question 40

The emf of cell 

image

It could be increased by :

  • Anode (Oxidation): 2Tl(s) -> 2Tl+(aq) + 2e
  • Cathode (Reduction): Cu+2(aq) + 2e -> Cu(s)
  • Overall Reaction: 2Tl(s) + Cu+2 ->2Tl+(aq) + Cu(s)

Nersnt Equation :

E_cell = E0_cell - (0.0591 / 2) * log([Tl+]^2 / [Cu2+])


The EMF of this specific cell can be increased by:

  1. Increasing the molarity of Cu+2 (e.g., from 0.01M to 0.1M).
  2. Decreasing the molarity of Tl+ ions (e.g., from 0.001M to 0.0001M).

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