Sign in
Please select an account to continue using cracku.in
↓ →
Reduction potential of ions are given below:
$$ClO_4^-$$: $$E° = 1.19$$ V; $$IO_4^-$$: $$E° = 1.65$$ V; $$BrO_4^-$$: $$E° = 1.74$$ V
The correct order of their oxidising power is:
Higher reduction potential means stronger oxidizing agent.
$$BrO_4^-: E° = 1.74$$ V (highest), $$IO_4^-: E° = 1.65$$ V, $$ClO_4^-: E° = 1.19$$ V (lowest).
Oxidising power order: $$BrO_4^- > IO_4^- > ClO_4^-$$.
The answer is Option (2): $$\boxed{BrO_4^- > IO_4^- > ClO_4^-}$$.
Create a FREE account and get:
Educational materials for JEE preparation