If each of the letters of the English alphabet is assigned an odd numerical value beginning with A = 1, B = 3 and so on, what will be the total value of the letters of the word RADICAL?

Given that A = 1, B =3 , C=5 , D=7 ..... And so on 

Then the alphabet position  followed $$ n^{th}   alphabet   = 2 \times n -1 $$

therefore the RADICAL total value     

R =$$ 2 \times 18 - 1 = 35 $$ (R = 18 alphabet position)

A = $$ 2 \times 1 - 1 = 1 $$ 

D = $$ 2 \times 4 - 1 = 7 $$

I = $$ 2 \times 9 - 1 = 17 $$

C  = $$ 2 \times 3 - 1 = 5 $$

A = $$ 2 \times 1 - 1 = 1 $$

L = $$ 2 \times  12 - 1 =  23 $$

Total value = 35+1+7+17+5+1+23 = 89 Ans