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A block of mass 5 kg is placed at rest on a table of rough surface. Now, if a force of 30 N is applied in the direction parallel to surface of the table, the block slides through a distance of 50 m in an interval of time 10 s. Coefficient of kinetic friction is (given, $$g = 10 \text{ m s}^{-2}$$):
Finding the average acceleration using kinematics:
$$s=ut+\frac{1}{2}at^2$$
$$50=0+\frac{1}{2}\times\ a\times\ 100$$
$$\therefore\ a=1\ ms^{-2}$$
Net force, $$F_{net}=F_{applied}-F_{friction}$$$$=ma$$
$$30-F_{friction}=5\times1=5$$
$$\therefore\ F_{friction}=25=\mu N=\mu mg=50\mu\ $$
$$\therefore\ \mu\ =\frac{25}{50}=0.5$$
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