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The Molarity (M) of an aqueous solution containing 5.85 g of NaCl in 500 mL water is: (Given: Molar Mass Na: 23 and Cl: 35.5 g mol⁻¹)
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Moles of NaCl = 5.85/58.5 = 0.1 mol
Volume = 500 mL = 0.5 L
Molarity = 0.1/0.5 = 0.2 M
The correct answer is Option 4: 0.2.
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