Question 37

In a certain code language, 'ABKN' is coded as '84', and 'PNCL' is coded as '135'. How will 'HONT' be coded in that language?

Solution

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The sum of the place values of the letters within the word is multiplied by 3 to obtain the code.

ABKN ==> 3$$\times$$(A+B+K+N) ==> 3$$\times$$(1+2+11+14) = $$3\times28$$ = 84

PNCL ==> 3$$\times$$(P+N+C+L) ==> 3$$\times$$(16+14+3+12) = $$3\times45$$ = 135

HONT ==> 3$$\times$$(H+O+N+T) ==> 3$$\times$$(8+15+14+20) = $$3\times57$$ = 171

So the code for 'HONT' is '171'.

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