Question 37

In a certain code language, 'ABKN' is coded as '84', and 'PNCL' is coded as '135'. How will 'HONT' be coded in that language?

Solution

The sum of the place values of the letters within the word is multiplied by 3 to obtain the code.

ABKN ==> 3$$\times$$(A+B+K+N) ==> 3$$\times$$(1+2+11+14) = $$3\times28$$ = 84

PNCL ==> 3$$\times$$(P+N+C+L) ==> 3$$\times$$(16+14+3+12) = $$3\times45$$ = 135

HONT ==> 3$$\times$$(H+O+N+T) ==> 3$$\times$$(8+15+14+20) = $$3\times57$$ = 171

So the code for 'HONT' is '171'.

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