Question 36

If 13A = 11B = 8C, find A : B : C

Solution

Let $$13A = 11B = 8C = k$$

=> $$A = \frac{k}{13}$$ , $$B = \frac{k}{11}$$ , $$C = \frac{k}{8}$$

=> Ratio of A : B : C = $$\frac{k}{13} : \frac{k}{11} : \frac{k}{8}$$

= $$\frac{1}{13}$$ : $$\frac{1}{11}$$ : $$\frac{1}{8}$$

L.C.M. of 8,11 and 13 = 1144, thus multiplying by 1144, we get :

= $$\frac{1144}{13} : \frac{1144}{11} : \frac{1144}{8}$$

= 88 : 104 : 143

=> Ans - (C)

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