Two trains are moving in the opposite directions at speed of 43 km/h and 51 km/h respectively. The time taken by the slower train to cross a man sitting in the faster train is 9 seconds. What is the length (in metres) of the slower train?

Speed of the two trains = 43 km/h and 51 km/h

Since the trains are moving in opposite directions, => Relative speed = 43 + 51 = 94 km/h

= $$(94\times\frac{5}{18})$$ m/s = $$(\frac{235}{9})$$ m/s

Since the observation given is of a passenger sitting in faster train, distance travelled is equal to length of the slower train. Let it be = $$d$$ m

Using, distance = speed x time

=> $$d=\frac{235}{9}\times9=235$$ m

=> Ans - (A)