I. 15x^2 - 11x + 2 =0
II. 10y^2 - 9y + 2 =0

I. 15x^2 - 11x + 2 =0
To find the roots of this equation use the formula  x1 = (-b +√(b^2 - 4ac))/2a ; substitute a = 15, b = -11, c = 2 we get x1 = 2/5 = 0.4
Similarly to find the another root x2 =  (-b -√(b^2 - 4ac))/2a; we get x2 = 1/3 =0.33
(x1, x2) = (0.4, 0.33)

II. 10y^2 - 9y + 2 =0
Similarly using the above formula we find the roots for 10y^2 - 9y + 2 =0 (a = 10, b = -9, c = 2)
(y1, y2) = (0.5, 0.4)

Comparing the roots (x1, x2) = (0.4, 0.33) with y1 =0.5
clearly y1 is greater than both x1 and x2.

Now compare the roots (x1, x2) with y2 = 0.4
Here we can observe x1 = y2 = 0.4

but x2<y2 i.e.,0.33<0.4

In all cases x<y except one case where x=y. So the answer should be x ≤ y.
Hence option 'C'.