A wire, when bent in the form of a square, encloses a region of area 121 $$cm^{2}$$ .If the same wire is bent in to the form of a circle, then the area of the circle is  use ($$\pi$$=$$\frac{22}{7}$$)

Area of square = $$ a^2 $$

a = side of the square

given area of the square = 121 $$cm^{2}$$

solving, a =11

same wire is bent in to the form of a circle

therefore, perimeter of the square = perimeter of the circle

perimeter of the square = 4a = $$ 4 \times a = 44 cm $$

44 = perimeter of the circle

$$ 44 = 2 \times \frac{22}{7} \times r $$

solving r = 7

area of the circle = $$ \pi r^2 $$

                           = $$ \frac{22}{7} \times 7^2 $$

                            = 154 $$cm^{2}$$