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Let us analyze each molecule for polarity:
- $$CCl_4$$: Tetrahedral, symmetric, dipole moments cancel. Non-polar.
- $$CO_2$$: Linear, symmetric, dipole moments cancel. Non-polar.
- $$CH_2=CH_2$$: Planar, symmetric. Non-polar.
- $$CHCl_3$$: Tetrahedral but asymmetric (one H, three Cl). Net dipole moment exists. Polar.
The answer is $$CHCl_3$$, which corresponds to Option (4).
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