Bond dissociation energy of E $$-$$ H bond of the "H$$_2$$E" hydrides of group 16 elements (given below), follows order.
(A) O
(B) S
(C) Se
(D) Te

We need to arrange the bond dissociation energies of E-H bonds in hydrides of group 16 elements (H$$_2$$E).

The group 16 elements in order are O, S, Se, and Te. As we move down the group, the atomic size increases, the E-H bond length increases, and the orbital overlap between E and H decreases. So the E-H bond dissociation energy decreases down the group.

The bond dissociation energies are approximately: O-H at 463 kJ/mol, S-H at 363 kJ/mol, Se-H at 276 kJ/mol, and Te-H at 266 kJ/mol.

Hence, the correct order is

which corresponds to $$A > B > C > D$$.

So, the answer is $$A > B > C > D$$.