Maximum number of electrons that can be accommodated in shell with $$n = 4$$ are:

Solution

The maximum number of electrons that can be accommodated in a shell with principal quantum number $$n$$ is given by

$$N = 2n^2$$

For $$n = 4$$,

$$N = 2 \times 4^2 = 2 \times 16 = 32$$

We can verify this by counting the subshells in the 4th shell: 4s has 2 electrons, 4p has 6, 4d has 10, and 4f has 14, giving a total of $$2 + 6 + 10 + 14 = 32$$ electrons.

So, the answer is $$32$$.

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Maximum number of electrons that can be accommodated in shell with $$n = 4$$ are:

Solution

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