Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
A light ray is incident on the surface of a sphere of refractive index $$n$$ at an angle of incidence $$\theta_0$$. The ray partially refracts into the sphere with angle of refraction $$\phi_0$$ and then partly reflects from the back surface. The reflected ray then emerges out of the sphere after a partial refraction. The total angle of deviation of the emergent ray with respect to the incident ray is $$\alpha$$. Match the quantities mentioned in List-I with their values in List-II and choose the correct option.
| List-I | List-II | ||
|---|---|---|---|
| (P) | If $$n = 2$$ and $$\alpha = 180°$$, then all the possible values of $$\theta_0$$ will be | (1) | $$30°$$ and $$0°$$ |
| (Q) | If $$n = \sqrt{3}$$ and $$\alpha = 180°$$, then all the possible values of $$\theta_0$$ will be | (2) | $$60°$$ and $$0°$$ |
| (R) | If $$n = \sqrt{3}$$ and $$\alpha = 180°$$, then all the possible values of $$\phi_0$$ will be | (3) | $$45°$$ and $$0°$$ |
| (S) | If $$n = \sqrt{2}$$ and $$\theta_0 = 45°$$, then all the possible values of $$\alpha$$ will be | (4) | $$150°$$ |
| (5) | $$0°$$ |
Create a FREE account and get:
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.