The electronic configuration for Neodymium is: [Atomic Number for Neodymium 60]

Neodymium (Nd) has atomic number 60. It is a lanthanide element. The noble gas core is Xenon (Xe, Z=54). After Xe, the electron filling order is: 6s, then 4f.

$$60 - 54 = 6$$ electrons to fill after Xe core.

First, 6s is filled: 2 electrons → $$6s^2$$ (4 remaining)

Then, 4f is filled: 4 electrons → $$4f^4$$

Electronic configuration: $$[Xe]\,4f^4\,6s^2$$.

The correct answer is Option 1: $$[Xe]\,4f^4\,6s^2$$.