Sign in
Please select an account to continue using cracku.in
↓ →
In a nuclear fission process, a high mass nuclide $$(A \approx 236)$$ with binding energy $$7.6$$ MeV/Nucleon dissociated into two middle mass nuclides $$(A \approx 118)$$, having binding energy of $$8.6$$ MeV/Nucleon. The energy released in the process would be _______ MeV.
Correct Answer: 236
In nuclear fission:
- Parent nucleus: $$A = 236$$, binding energy per nucleon = 7.6 MeV
- Two daughter nuclei: each $$A = 118$$, binding energy per nucleon = 8.6 MeV
Total binding energy before = $$236 \times 7.6 = 1793.6$$ MeV
Total binding energy after = $$2 \times 118 \times 8.6 = 236 \times 8.6 = 2029.6$$ MeV
Energy released = Final BE - Initial BE = $$2029.6 - 1793.6 = 236$$ MeV
The answer is $$\boxed{236}$$ MeV.
Create a FREE account and get:
Educational materials for JEE preparation