Four number-sets have been given below, out of which three are alike in some manner and one is different. Select the number-set that is different from the rest.

(84, 116, 181) $$\longrightarrow\ $$ 116 - 84 = 32 and 181 - 116 = 65

(44, 89, 179) $$\longrightarrow\ $$ 89 - 44 = 45 and 179 - 89 = 90

(71, 108, 182) $$\longrightarrow\ $$ 108 - 71 = 37 and 182 - 108 = 74

(35, 81, 173) $$\longrightarrow\ $$ 81 - 35 = 46 and 173 - 81 = 92

The difference between third and second number is twice the difference between second and first number except in (84, 116, 181).

$$\therefore\ $$(84, 116, 181) is the different one among the given number number-sets.

Hence, the correct answer is Option A