Question 30
A set of all possible values the function $$f(x)=\frac{x}{|x|}$$, where $$x \neq 0$$ takes is,
Solution
As already given $$X\ne0\ ,\ we\ can\ say\ either\ X\ can\ be\ positive\ or\ negative\ ,\ that\ is\ 2\ cases\ :$$
If x>0 :
|x| = x , Hence f(x) = 1 for x > 0.
Else if, x < 0:
|x| = -x , Hence f(x) = -1 for x < 0.
Therefore, {1,-1} are possible values of f(x).
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