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Given in the figure are two blocks A and B of weight 20 N and 100 N, respectively. These are being pressed against a wall by a force F and kept in equilibrium as shown. If the coefficient of friction between the blocks is 0.1 and between block B and the wall is 0.15, the frictional force applied by the wall on block B is:
$$W_{total} = W_A + W_B$$
$$W_{total} = 20\ \text{N} + 100\ \text{N} = 120\ \text{N}$$
The only external force acting upwards to prevent the system from falling is the frictional force ($$f_w$$) exerted by the wall on block B.
Since the system is in equilibrium, the net vertical force is zero, i.e., $$\sum F_y = 0$$
$$f_w - W_{total} = 0$$
$$f_w = W_{total}$$
$$f_w = 120\ \text{N}$$
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