Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
A series LCR circuit consists of $$R = 80$$ $$\Omega$$. $$X_L = 100$$ $$\Omega$$, and $$X_C = 40$$ $$\Omega$$. The input voltage is 2500 $$\cos(100\pi t)$$ V. The amplitude of current, in the circuit, is ______ A.
Correct Answer: 25
We are given a series LCR circuit with $$R = 80$$ $$\Omega$$, $$X_L = 100$$ $$\Omega$$, $$X_C = 40$$ $$\Omega$$, and input voltage $$V = 2500\cos(100\pi t)$$ V.
$$ Z = \sqrt{R^2 + (X_L - X_C)^2} $$
$$ Z = \sqrt{80^2 + (100 - 40)^2} = \sqrt{6400 + 3600} = \sqrt{10000} = 100 \text{ } \Omega $$
From $$V = 2500\cos(100\pi t)$$, the amplitude (peak voltage) is $$V_0 = 2500$$ V.
$$ I_0 = \frac{V_0}{Z} = \frac{2500}{100} = 25 \text{ A} $$
The amplitude of current in the circuit is 25 A.
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.