The perimeters of a square and a rectangle are equal . If their area be 'A' m2 and 'B' m2 then correct statement is
Let side of square = $$s$$ and length and breadth of rectangle be $$l$$ and $$b$$ respectively.
According to ques, Perimeter of square = Perimeter of rectangle
=> $$4s=2(l+b)$$
=> $$2s=l+b$$
Thus, $$l,s,b$$ are in A.P. and $$s^2$$ > $$lb$$
For example : $$4,6,8$$ where $$6^2$$ > $$4\times8$$
Thus, A > B
=> Ans - (C)
Create a FREE account and get:
