Question 26

Two numbers are 50% and 90% lesser than a third number. By how much percent is the second number to be enhanced to make it equal to the ﬁrst number?

Solution

Let third number = $$100x$$

First number is 50% less than $$100x$$ and second number is 90% less than $$100x$$

=> First number = $$50x$$ and Second number = $$10x$$

To make second number equal to first number, it should be enhanced by = $$50x - 10x = 40x$$

=> Required % = $$\frac{40x}{10x} \times 100 = 4 \times 100 = 400\%$$

=> Ans - (D)

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