Question 26

If the length of a rectangle is increased by 10% and its breadth is decreased by 10%, then its area

assume original length of rectangle = 100

original breadth = 100

original area = 10000

now  length of a rectangle is increased by 10%

new length = $$ 100 \times \frac{110}{100}  = 110 $$

breadth is decreased by 10%

new breadth = $$ 100 \times \frac{90}{100} = 90 $$

new area = $$ 110 \times 90 = 9900 $$

% change in area = $$ \frac{10000 - 9900}{10000} \times 100 = \frac{100}{10000} \times 100 = 1$$ %

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