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The $$K_{sp}$$ of $$Ag_{2}CrO_{4}$$ is $$1.1\times10^{-12}$$ at 298 K. The solubility (in $$\frac{mol}{L}$$) of $$Ag_{2}CrO_{4}$$ in a $$0.1M \ AgNO_{3}$$ solution is
$$1.1\times10^{-11}$$
$$1.1\times10^{-10}$$
$$1.1\times10^{-12}$$
$$1.1\times10^{-9}$$
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