Question 24

A reduction of 10% in the price of tea enables a dealer to purchase 25 kg more tea for Rs. 22500. What is the reduced price per kg of tea?

Solution

let the original price of tea = Rs x Kg

After reduction the price becomes = x - 10% of x = $$ \frac{9x}{10} $$ / kg

Now

$$ (\frac{22500}{\frac{9x}{10}}) - \frac{22500}{x} = 25 $$

$$ 22500 ( \frac{10}{9x} - \frac{1}{x} ) = 25 $$

solving x = 100

hence new price = 90

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