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A power transmission line feeds input power at 2300 V to a step down transformer with its primary windings having 4000 turns. The output power is delivered at 230 V by the transformer. If the current in the primary of the transformer is 5 A and its efficiency is 90%, the output current would be:
We have a power transmission line that supplies an input (primary) voltage of $$V_p = 2300 \text{ V}$$ to a step-down transformer. The number of turns on the primary winding is given as $$N_p = 4000$$. The transformer delivers an output (secondary) voltage of $$V_s = 230 \text{ V}$$.
The current in the primary circuit is stated to be $$I_p = 5 \text{ A}$$. The transformer works with an efficiency of $$\eta = 90\% = 0.90$$. Our goal is to compute the secondary (output) current $$I_s$$.
First, we recall the definition of efficiency for a transformer:
$$\eta \;=\; \dfrac{P_{\text{out}}}{P_{\text{in}}}$$
Here, $$P_{\text{in}}$$ is the input power and $$P_{\text{out}}$$ is the output power.
We now calculate the input power using the elementary electric power formula $$P = V I$$:
$$P_{\text{in}} \;=\; V_p \, I_p$$
Substituting the given values,
$$P_{\text{in}} \;=\; 2300 \text{ V} \times 5 \text{ A} \;=\; 11500 \text{ W}$$
Next, we find the output power from the efficiency relation. Rearranging the efficiency formula, we get
$$P_{\text{out}} \;=\; \eta \, P_{\text{in}}$$
Putting the numbers in,
$$P_{\text{out}} \;=\; 0.90 \times 11500 \text{ W}$$
$$P_{\text{out}} \;=\; 10350 \text{ W}$$
The transformer’s secondary voltage is already given as $$V_s = 230 \text{ V}$$. Again using the power formula on the secondary side,
$$P_{\text{out}} \;=\; V_s \, I_s$$
We solve for the unknown secondary current $$I_s$$:
$$I_s \;=\; \dfrac{P_{\text{out}}}{V_s}$$
Substituting $$P_{\text{out}} = 10350 \text{ W}$$ and $$V_s = 230 \text{ V}$$, we obtain
$$I_s \;=\; \dfrac{10350}{230} \text{ A}$$
Performing the division,
$$I_s \;=\; 45 \text{ A}$$
So, the secondary winding of the transformer delivers a current of $$45 \text{ A}$$.
Hence, the correct answer is Option D.
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