Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
A boy pushes a box of mass 2 kg with a force $$\vec{F} = (20\hat{i} + 10\hat{j})$$ N on a frictionless surface. If the box was initially at rest, then ______ m is displacement along the $$x$$-axis after 10 s
Correct Answer: 500
The force applied on the box is $$\vec{F} = (20\hat{i} + 10\hat{j})$$ N and the mass of the box is $$m = 2$$ kg. The surface is frictionless and the box starts from rest.
The acceleration along the $$x$$-axis is $$a_x = \frac{F_x}{m} = \frac{20}{2} = 10 \text{ m/s}^2$$.
Using the kinematic equation for displacement with initial velocity zero: $$x = \frac{1}{2}a_x t^2 = \frac{1}{2} \times 10 \times (10)^2 = \frac{1}{2} \times 10 \times 100 = 500 \text{ m}$$.
Therefore, the displacement along the $$x$$-axis after 10 s is 500 m.
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.