The dimensional formula of angular impulse is :

We need to find the dimensional formula of angular impulse.

Angular impulse is the product of torque and time, giving Angular impulse = $$\tau \times t$$.

Torque ($$\tau$$) is force times the lever arm (perpendicular distance). The dimension of force is $$[M L T^{-2}]$$ and that of the lever arm is $$[L]$$, so $$[\tau] = [M L T^{-2}] \times [L] = [M L^2 T^{-2}]$$.

Thus the dimension of angular impulse is $$[\text{Angular impulse}] = [\tau] \times [t] = [M L^2 T^{-2}] \times [T] = [M L^2 T^{-1}]$$.

The correct answer is Option D: $$[M L^2 T^{-1}]$$.