Question 189

Satish start from A and walks 2 km east upto B and turns southwards and walks 1 km upto C. At C he turns to east and walks 2 km upto D. He then turns northwards and walks 4 km to E. How far is he from his starting point ?

Solution

the above mentioned route can be traced as follows :

$$AE=\sqrt{4^{2}+3^{2}}=5km$$
the distance between A and E that is the start and the finish points will can be found out using the Pythagoras theorem.
$$\sqrt{3^{2}+4^{2}}=5$$
hence the correct answer is option A.


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