Question 188

The sum of the squares of two consecutive positive numbers is 1861. What are the two numbers ?

Solution

Let two consecutive numbers be $$(x)$$ and $$(x+1)$$

Acc to ques :

=> $$(x)^2 + (x+1)^2 = 1861$$

=> $$2x^2 + 2x + 1 - 1861 = 0$$

=> $$x^2 + x - 930 = 0$$

=> $$x^2 + 31x - 30x - 930 = 0$$

=> $$x(x+31) - 30(x+31) = 0$$

=> $$(x+31) (x-30) = 0$$

=> $$x = 30 , -31$$

Since, numbers are positive, => $$x = -31$$ is not possible.

=> Numbers are = 30 & 31

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: