Question 17

If $$\log_{5}\log_{8}(x^2 - 1) = 0$$, then a possible value of x is

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$$\log_{5}\log_{8}(x^2 - 1) = 0$$

$$\log_{8}(x^2 - 1) = 1$$

$$(x^2 - 1) = 8$$

$$x^2=9$$

$$x=3\ or\ x=-3$$

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