ΔABC is a right angled triangle with AB = 6 cm, AC = 8 cm, ∠BAC = 90′. Then the radius of the incircle is

NOTE :- Area of triangle = (semi perimeter) * (inradius)

AB = 6 cm , AC = 8 cm and $$\angle$$BAC = 90°

From $$\triangle$$ABC,

BC = $$\sqrt{(AB)^2+(AC^2)}$$

= $$\sqrt{6^2+8^2} = \sqrt{36+64}$$

= 10 cm

Semi perimeter of $$\triangle$$ABC = s

= $$\frac{6+8+10}{2}$$ = 12 cm

Area of $$\triangle$$ABC = $$\frac{1}{2}$$*AB*AC

= $$\frac{1}{2}$$*6*8 = 24 $$cm^2$$

=> Inradius = $$\frac{\triangle}{s}$$ = $$\frac{24}{12}$$

= 2 cm