Two trains are moving in the same direction at the speed of 23 km/hr and 77 km/hr. The time taken by faster train to cross a man sitting in the slower train is 40 seconds. What will be the length (in metres) of the faster train?
Let length of faster train = $$l$$ m
The trains are moving in the same direction, thus relative speed = $$77-23=54$$ km/hr = $$(54\times\frac{5}{18})=15$$ m/s
Time taken = 40 seconds
Using, distance = speed $$\times$$ time
=> $$l=15\times40=600$$ m
=> Ans - (C)
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