Instructions

In the following questions two equations numbered I and II are given. You have to solve both equations and
Give answer If

a. x ˃ y
b. x ≥ y
c. x ˂ y
d. x ≤ y
e. x = y or the relationship cannot be established

Question 159

I. $${x^2}$$ + 8x + 15 = 0
II. $${y^2}$$ + 11y + 30 = 0

Solution

I.$$x^{2} + 8x + 15 = 0$$

=> $$x^2 + 5x + 3x + 15 = 0$$

=> $$x (x + 5) + 3 (x + 5) = 0$$

=> $$(x + 5) (x + 3) = 0$$

=> $$x = -5 , -3$$

II.$$y^{2} + 11y + 30 = 0$$

=> $$y^2 + 5y + 6y + 30 = 0$$

=> $$y (y + 5) + 6 (y + 5) = 0$$

=> $$(y + 6) (y + 5) = 0$$

=> $$y = -6 , -5$$

$$\therefore x \geq y$$

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I. $${x^2}$$ + 8x + 15 = 0II. $${y^2}$$ + 11y + 30 = 0