In the following questions two equations numbered I and II are given. You have to solve both equations and
Give answer If
a. x ˃ y
b. x ≥ y
c. x ˂ y
d. x ≤ y
e. x = y or the relationship cannot be established
I : $$2x - 3y = -3.5$$
II : $$3x + 2y = -6.5$$
Multiplying eqn(I) by 2 and eqn(II) by 3, and then adding both equations, we get :
=> $$(4x + 9x) + (-6y + 6y) = (-7 -19.5)$$
=> $$13x = -26.5$$
=> $$x = \frac{-26.5}{13} \approx -2$$
=> $$y = \frac{3x + 6.5}{2} = 0.25$$
Hence $$x < y$$
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