Question 149

Three pipes X. Y and Z discharge three different chemicals A. B and C in a tank. The pipes can fill the tank in 20. 25 and 40 minutes respectively. What will be the proportion of chemical B in the tank, if all the pipes are open for 10 minutes?

Solution

In 1 minute A,B and C together can fill the tank is$$=(1/20)+(1/25)+(1/40)$$

$$=(10+8+5)/200$$

$$=23/200.$$

So,in 10 minutes they can fill $$(230/200).$$

B can fill in 10 minutes is$$=10/25.$$

So, proportion in B will be

$$=(200/230)×(10/25).$$

$$=8/23.$$

So, C is correct choice.

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