Two equal sums(in ₹) are lent at 8% and 4% simple interest p.a, respectively at the same time.The first sum is received 2 years earlier than the other and the amount received in each case is ₹14,500. Each sum is:

As per the given data in the question,

$$R_1=8\%$$ and $$R_2=4\%$$

Let the time is t and the amount =P

$$SI=\dfrac{PRT}{100}$$

As per the condition given in the question,

$$\Rightarrow 14500-P=\dfrac{P\times 8\times t}{100}-------(i)$$

and $$14500-P=\dfrac{P\times 4\times(t+2)}{100}-----(ii)$$

From the equation (i) and (ii)

t =2 years,

Now substituting the values of t in the equation (i)

$$\Rightarrow 14500-P=\dfrac{P\times 8\times 2}{100}$$

$$P=\dfrac{14500\times 25}{29}=Rs. 12500$$