The radii of a sphere and a right circular cylinder are 3 cm each, If their volumes are equals, then curved surface area of the cylinder is

Radius of the sphere ($$r_1$$) = 3 cm

Radius of the right circular cylinder ($$r_2$$) = 3 cm

Let the height of the right circular cylinder = h

Volume of sphere = Volume of right circular cylinder

$$=$$>  $$\frac{4}{3}\pi\ \left(r_1\right)^3=\pi\ \left(r_2\right)^2h$$

$$=$$>  $$\frac{4}{3}\pi\ \left(3\right)^3=\pi\ \left(3\right)^2h$$

$$=$$>  h = 4 cm

Height of the right circular cylinder = 4 cm

$$\therefore\ $$The curved surface area of the cylinder = $$2\pi\ r_2h=2\times\frac{22}{7}\times3\times4=\frac{528}{7}=75\frac{3}{7}cm^2$$

Hence, the correct answer is Option A